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(1/5)^2-x=7
We move all terms to the left:
(1/5)^2-x-(7)=0
determiningTheFunctionDomain -x-7+(1/5)^2=0
We add all the numbers together, and all the variables
-x-7+(+1/5)^2=0
We add all the numbers together, and all the variables
-1x-7+(+1/5)^2=0
We multiply all the terms by the denominator
-1x*5)^2-7*5)^2+(+1=0
Wy multiply elements
-25x^3=0
We do not support expression: x^3
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